[LeetCode每日一题]264. Ugly Number II
2020/3/16小于 1 分钟
题目如下:
Write a program to find the n-th ugly number.
Ugly numbers are positive numbers whose prime factors only include 2, 3, 5.
Example:
Input: n = 10
Output: 12
Explanation: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 is the sequence of the first 10 ugly numbers.
Note:
1.1 is typically treated as an ugly number.
2.n does not exceed 1690.
264. Ugly Number II 这道题让我们找出第n大的ugly数,ugly数是什么请看[LeetCode每日一题]263. Ugly Number。假设初始时ugly数只有2,3,5,新生成的ugly数都是由原来的ugly数乘2, 乘3, 乘5得来,由此便可以写出代码。
class Solution {
public int nthUglyNumber(int n) {
if (n <= 0 || n > 1690) return -1;
int[] uglys = new int[n];
uglys[0] = 1;
int p2 = 0, p3 = 0, p5 = 0;
for (int i = 1; i < n; i++) {
uglys[i] = Math.min(uglys[p2] * 2, Math.min(uglys[p3] * 3, uglys[p5] * 5));
if (uglys[p2] * 2 == uglys[i]) p2++;
if (uglys[p3] * 3 == uglys[i]) p3++;
if (uglys[p5] * 5 == uglys[i]) p5++;
}
return uglys[n - 1];
}
}